Question

find the diameter of sun in km supposing that it subtends an angle of 32' at the eye of an observer. give that the distance of the sun is 91×10^6​

Answer 1

Step-by-step explanation:

given : tita =32

l= 91×10 power 6

we know that

1= 1/60

so we can write

32= (32/60)=(8/15)

tan (8/15) = AB/0A =d/l

tan (8/15) = d/91×10power 6

d = 91×10power6 × tan (8/15) km

d= 8.4175 ×10the power 5 km