Question

Find the diameter of the circle whose area is equal to the sum of the area of two circles of diameter 20 m and 24 m.....​

Answer 1

Answer:

Here, The Diameter of the bigger circle is 4root(61)m.

Here, As per our given question,

=Area of the first circle=Sum of the area of other two circles,

Radius=20m=10m

=24m=12m

=So,Sum of the Area of the two other circles=pie ×r^2+pie×r×2

=[22/7×10×10]+[22/7×12×12]

=(2200/7)+(3168/7)

=(2200+3168)/7

=5368/7

=766.85m^2

Now, Areaof the first circle=766.85m^2

So, its Radius= Area=pie×r^2

=766.85=22/7×r^2

=766.85×7=22r^2

=(766.85×7)/22=r^2

=5367.95/22=r^2

=243.99

=244=r^2 (by rounding off)

So, by doing square root on both sides, we get,

=r=2root(61)m

So, Now its Diameter=2×2root(61)

=4root(61)m.

So, The diameter of the bigger circle is 4root(61)m.

Thank you.