Question

find the diffential equation of elips who majure axis is twice it major axis​

Answer 1

x + 4y dy/dx = 0

Step-by-step explanation:

Let 2a and 2b be lengths of major axis and minor axis of the ellipse.

Then 2a =2(2b)

a = 2b

equation of the ellipse is

x^2/a^2 + y^2/b^2 =1

x^2/(2b)^2 + y^2/b^2 =1

x^2/4b^2 +y^2/ b^2 =11

x^2 + 4y^2 = 4b^2

Differentiating w.r.t.x, we get

2x + 4 ×2y dy/dx = 0

x + 4y dy/dx =0

This is the required D.E