Question

find the difference between ci and si on 12000 an in 3÷2 at 10 % compounded half yearly

Answer 1

please mark it as a brainliest answer

Answer 2

Heya ☺

Given that

P = 12,000

R = 10 % p.a.

T = 3/2 years

Solution

When the interest is compounded half yearly

A = P(1+R/100)^n

= 12,000(1+10/200)^3/2

= 12,000(200+10/200)^3/2 × 2

= 12,000(210/200)^3

= 12,000(21/20)^3

= 12,000 × 9,261/8,8000

= ₹13,891.50

C.I. = A - P

= ₹(13,891.50 - 12,000)

= ₹1,891.50


S.I. = P×R×T/100

= 12,000×10×3/100×2

= ₹1,800

Difference = C.I. - S.I.

= ₹(1,891.50 - 1,800)

= ₹91.50




Thanks