Math, asked by abhisrees, 10 months ago

Find the difference between
compound interest and simple
interest on 15000 at 12% per
annum for 3 years ( compounded
annualy​

Answers

Answered by anishka56
8

\huge\underline\orange{\sf Hey}

principle = 15000

Rate = 12%

Time = 3 years

Amount =

p \: (1 +  \frac{r}{100}) {}^{3}

15000(1 +   \frac{12}{100} ) {}^{3}

15000(1 +  \frac{3}{25} ) {}^{3}

15000( \frac{25 + 3}{25} ) {}^{3}

15000( \frac{28}{25} ) {}^{3}

15000 \times  \frac{28}{25}  \times  \frac{28}{25}  \times  \frac{28}{25}

21952

CI = Amount - Principle

21952 - 15000

 =  >  \: 6952

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Answered by xBeardoBoy01
7

Answer:

Your answer is 6952................

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