water is flowing through a cylindrical pipe,of internal diameter 2 cm,into a cylindrical tank of base radius 40 cm,at the rate of 0.4 m/s,determine the rise in level of water in the tank in 1/2 of an hour.
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45cm
Step-by-step explanation:
Speed of water flowing in hr= height of pipe
0.4m/s= 1.44km/h
1.44km/h= 1 hr
Therefore, half an hour= 1.44/2 = 0.72km
converting 0.72km to cm
= 72000cm
now volume of water flowing through pipe in 1/2 hr= volume of vessel in half an hour
22/7*1*1*72000=22/7*40*40*h (h=rise in height of water in vessel where water is transferred)
on simplification
h=45cm
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