Question

Find the difference between compound interest and simple interest on rs12000 in 1×1/2 years at 10% compounded half yearly​

Answer 1

Answer:

12060 Rs

Step-by-step explanation:

P= Rs 12000

R =10 %

T= 1*1/2 years

CI ( time = fraction) = P* (1+r/100)^whole part of the time*(1+fraction*R/100)

   = 12000 (1+10/100)1  *  (1+1/2*10/100)

   = 12000(110/100) * (1+5/100)

   =120 * 110 *105 /100

   =12 * 11 * 105

   =13860 Rs

SI = PTR/100

   = 1600*3/2*10/100

   = 1800 Rs

CI - SI

= 12060 Rs

Hope this helps .

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Thank you :):)

Answer 2

${\huge{\boxed{\tt{\color{red}{Aɴꜱᴡᴇʀ}}}}}$

$➜ \large \tt{} \purple{C.I-S.I = 91.5 \: rupees}$

________________________________________________

$\huge \sf {\orange {\underline {\pink{\underline {Gɪᴠᴇɴ}}}}}$

• ✭ Principal (p) = 12000
• ✭ Time (t) = $\tt1\frac{3}{2}1$
• ✭ Rate (r) = 4%

______

$\begin{gathered}\Large{\purple{\underline{\textsf{\textbf{To Find\::}}}}} \\ \end{gathered}$

☞ The difference between the simple interest and the compound interest.

__________________________________________

$\begin{gathered}\orange\bigstar\:{\underline{\pink{\boxed{\bf{\gray\:Steps}}}}}}}}\:\green\bigstar \\ \end{gathered}$

❍ First let's find the value of simple interest. And it is given by,$\large \tt{}S.I = \frac{p \times r \times t}{100}$

Substituting our given values,

$\large \tt \leadsto{}S.I = \frac{12000 \times 10\times 3}{100 \times 2} \\ \\ \large \tt \leadsto{}S.I = \cancel\frac{360000}{200} \\ \\ \large\tt \leadsto{ \pink{1800\: rupees}}$

➤ So next let's find the value of A. And its given by,

$\large \tt{}A = p(1 + \frac{ \frac{r}{2} }{100} {)}^{2t}$

➤ Substituting the given values,

$\begin{gathered} \dashrightarrow \large \tt{}A = 12000(1 + \frac{ \frac{10}{2} }{100} {)}^{2( \frac{3}{2} )} \\ \\ \tt \large \dashrightarrow12000(1 + 0.05 {)}^{3} \\ \\ \tt \large \dashrightarrow12000 \times 1.157625 \\ \\ \tt \large \dashrightarrow{ \red{A = 13891 .5\: rupees}}\end{gathered}$

➤ So now we can find the compound interest with the use of A-p

$\begin{gathered}\large \tt{} \longrightarrow{}C.I = 13891.5 - 12000\\ \\ \tt \large \longrightarrow{} \pink{C.I =1891.5 \: rupees}\end{gathered}$

➤ Now we can find their difference by,

$\begin{gathered}\large \tt \hookrightarrow C.I-S.I = 1891.5- 1800 \\ \\ \large \tt \orange{\hookrightarrow{}C.I-S.I =91.5 \: rupees}\end{gathered}$