Question

Find the difference between compound interest and simple interest on

Rs 45000 at 12% per annum for 3 year.​

Answer 1

$\huge\blue{HELLO\:\:MATE}$

$\huge\sf{QUESTION}$

Find the difference between compound interest and simple interest on Rs 45000 at 12% per annum for 3 year.

$\huge\sf{ANSWER}$

PRINCIPLE (P)= Rs 45000

RATE OF INTEREST= 12% PER ANNUM

TIME= 3 YEARS

SIMPLE INTEREST (SI)=

$\frac{PTR}{100} \\ \\ = \frac{45000 \times 3 \times 12}{100} \\ \\ = Rs21600$

COMPOUND INTEREST=${p(1 + \dfrac{r}{100} )} ^{t} - p \\ \\ = 45000{( \frac{112}{100} )} ^{3} - 45000 \\ \\ = 45000 \times \frac{28}{25} \times \frac{28}{25} \times \frac{28}{25} - 45000 \\ \\ = 63221.76 - 45000 \\ \\ = Rs18221.76$

SI - CI

=21600-18221.76

=Rs3378.24

THEREFORE, THE DIFFERENCE BETWEEN CI AND SI is Rs 3378.24

Answer 2

Answer:

PRINCIPLE (P)= Rs 45000

RATE OF INTEREST= 12% PER ANNUM

TIME= 3 YEARS

SIMPLE INTEREST (SI)=

\begin{gathered}\frac{PTR}{100} \\ \\ = \frac{45000 \times 3 \times 12}{100} \\ \\ = Rs21600\end{gathered}

100

PTR

=

100

45000×3×12

=Rs21600

COMPOUND INTEREST=\begin{gathered}{p(1 + \dfrac{r}{100} )} ^{t} - p \\ \\ = 45000{( \frac{112}{100} )} ^{3} - 45000 \\ \\ = 45000 \times \frac{28}{25} \times \frac{28}{25} \times \frac{28}{25} - 45000 \\ \\ = 63221.76 - 45000 \\ \\ = Rs18221.76\end{gathered}

p(1+

100

r

)

t

−p

=45000(

100

112

)

3

−45000

=45000×

25

28

×

25

28

×

25

28

−45000

=63221.76−45000

=Rs18221.76

SI - CI

=21600-18221.76

=Rs3378.24

THEREFORE, THE DIFFERENCE BETWEEN CI AND SI is Rs 3378.24