Question

Find the difference between Compound interest and simple interest on ₹12000 and in 1 whole 1 upon years at 10% compounded half yearly​

Answer 1

Question:

Find the difference between Compound interest and simple interest on ₹12000 and in 1 whole 1 upon years at 10% compounded half yearly

Given:

→$P=₹12000$

→$T = 1 \dfrac{1}{2}$

→$R = 10\%$

$\blue{part </strong><strong>\</strong><strong>:</strong><strong>1:}$

To find SI:

$formula \: used: \\ </strong><strong>S</strong><strong>i = \dfrac{p \times r \times t}{100}$

Step by step explanation:

Step 1:

→$</strong><strong>S</strong><strong>i = \dfrac{12000 \times3 \times 10 }{100}$

Step 2:

→$</strong><strong>S</strong><strong>i = 600 \times 3$

Step 3:

→$</strong><strong>S</strong><strong>i = ₹18000</strong><strong>✓</strong><strong>$

$\blue{part \: 2:}$

To find CI:

Formula used:

$</strong><strong>C</strong><strong>i =p [ {(1 + \dfrac{r}{100})}^{t} - 1 ]$

Step by step explanation:

Step 1:

→$</strong><strong>C</strong><strong>i =12000 [ {(1 + \dfrac{5}{100})}^{3} - 1 ]$

Step 2:

→$</strong><strong>C</strong><strong>i = 12000[( \dfrac{9261}{8000} ) - 1]$

Step 3:

→$</strong><strong>C</strong><strong>i = 12000( \dfrac{9261 - 8000}{8000} )$

Step 4:

→$</strong><strong>C</strong><strong>i = 12000( \dfrac{1261}{8000} )$

Step 5:

→$</strong><strong>C</strong><strong>i = \dfrac{12000 \times 1261}{8000}$

Step 6:

→$</strong><strong>C</strong><strong>i = \dfrac{3783}{2}$

Step 7:

→$</strong><strong>C</strong><strong>i =₹ 1891.5</strong><strong>✓</strong><strong>$

$\blue{</strong><strong>part\</strong><strong>:</strong><strong> 3:}$

To find difference of ci and si:

Formula used:

$</strong><strong>C</strong><strong>i - </strong><strong>S</strong><strong>i$

Step 1:

→$= ₹1819.5 - ₹1800$

Step 2:

→$</strong><strong>\red{</strong><strong> = ₹91.5✓</strong><strong>}</strong><strong>$

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