Math, asked by 130298shrikeerthimut, 4 months ago

Find the difference between compound interest and Simple interest on
Rs.63100 at 10% p.a. for 2 years

Answers

Answered by vaishnavidutt1501232
7

Answer:

63731  is your answer

please mark it brainlist

Step-by-step explanation:

simple interest  = p*r*t/100

                         = (63100*10*2)/100

                            = 12620

compund interest = p*(r/100+1) ^t

                                 =63100(10/100+1)^2

                               = 63100(1.1)^2

                                  =76351

difference in simple and compound interest = 76351-12620

                                                                         =  63731

Answered by itzBrainlystarShivam
7

\Huge\boxed {r.s=631}

\Large{\textsf{\textbf{\underline{\underline{Given\::}}}}} \\

p = rs.63100

r = 10\%p.a.

t = 2 \: years.

\Large{\textsf{\textbf{\underline{\underline{To.find\::}}}}} \\

●diffrence \: between  \\ \: ci \: and \: si

\Large{\textsf{\textbf{\underline{\underline{formulas.used\::}}}}} \\

si =  \frac{prt}{100}

A = p \:   (1 +  \frac{r}{100} )t

c.i = a-p

\Large{\textsf{\textbf{\underline{\underline{solusion\::}}}}} \\

{\bf{1.case\::}} \\

➣to \: find \: s.i.

➣we \: know, \:

➣s.i. =  \frac{p \times r \times t}{100}

➣s.i. =  \frac{63100 \times  10 \times 2}{100}

\small{\textsf{\textbf{\underline{\underline{ ➣s.i = 12620\::}}}}} \\

{\bf{2.case\::}} \\

➣to \: find \: ci,

➣we \: know, \:

➣A = p(1 +  \frac{r}{100} )t

➣a = 63100(1 +  \frac{10}{100} ) {}^{2}

➣a = 63100(100 +  \frac{10}{100} ) {}^{2}

➣a = 63100( \frac{110}{100} ) {}^{2}

➣a = 63100  \times  \frac{110}{100} \times  \frac{110}{100}

\small{\textsf{\textbf{\underline{\underline{➣A = 76351\::}}}}} \\

{\bf{3.case\::}} \\

➣to.find.c.i

➣we.know. c.i = A - p

➣c.i = 76351 - 63100

\small{\textsf{\textbf{\underline{\underline{➣c.i = 13251\::}}}}} \\

\small{\textsf{\textbf{\underline{\underline{now.finding.the.diffrence.between.ci.and.si\::}}}}} \\

➣c.i = 13251

➣s.i = 12620

➣difference = r.s  (13251 - 12620)

\Large{\textsf{\textbf{\underline{\underline{➣r.s = 631\::}}}}} \\

\Large{\textsf{\textbf{\underline{\underline{form.the.solusion\::}}}}} \\

●p = principal \\ ●r = rate \: of \: interest \\ ●t = time \\ ●si = simple \: interest \\ ●ci  = compound \: interest \\ ●a = amount

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