Question

find the difference between compound interest and simple interest on sum of rs 12000 at the rate other 12% p.a for 2 years


plz give this questions answer I will mark brainliest

Answer 1

SOLUTION :

Principal (P) = Rs 12000

Rate of Interest (R) = 12% per annum

Time (T) = 2 years

To be found :-

The difference between Compound Interest (C.I) ans Simple Interest (S.I)

Simple Interest (S.I) = $\bf \frac{P \times R \times T}{100}$

Simple Interest (S.I) = $\bf \frac{12000 \times 12 \times 2}{100}$

Simple Interest (S.I) = $\bf 2880$

∴ Simple Interest (S.I) = Rs 2880

Now,

Compound Interest (C.I) = $\bf P[ (1+\frac{R}{100})^T-1]$

Compound Interest (C.I) = $\bf 12000[ (1+\frac{12}{100})^2-1]$

Compound Interest (C.I) = $\bf 12000[ (1+\frac{3}{25})^2-1]$

$as\: \frac{12}{4}=3 \:and\: \frac{100}{4}=25$

Compound Interest (C.I) = $\bf 12000[(\frac{25+3}{25})^2-1]$

Compound Interest (C.I) = $\bf 12000[(\frac{28}{25})^2-1]$

Compound Interest (C.I) = $\bf 12000[\frac{784}{625}-1]$

Compound Interest (C.I) = $\bf 12000[\frac{784-625}{625}]$

Compound Interest (C.I) = $\bf 12000\times \frac{159}{625}$

Compound Interest (C.I) = $\bf 3052.8$

∴ Compound Interest (C.I) = Rs 3052.8

So,

Difference between (C.I) ans (S.I) is

= Rs 3052.8 - Rs 2880

= Rs 172.8

Answer 2

Step-by-step explanation:

This is my answer I hope that it's really helpful for you ! Thanks