Math, asked by amirbhat286, 1 year ago

find the difference between SI and CI on rs 12000 at 9% per annum for 2 years

Answers

Answered by pavanrockman
58
SI=P*t*r/100
=12000*2*9/100
=2160

CI=p(1+r/100)²-p
=12000(1+.09)²-12000
=(12000*1.1881)-12000
=14,257.20-12000
=2257.20

Difference btw CI and SI is
2257.20-2160=97.20
Answered by mpsamratumpbrbkj
18
p=12000
ri or rate =9%
time=2 years

first we can do simple interest
=p*r*t\100
=12000*9*2/100
=2160

compound interest
ci= p*[(1+r/100)^t-1]
=12000*[(1+9/100)^2-1]
=12000*[(109/100)^2-1]
=12000*[11881/10000-1]
=12000*1881/10000
=12*1881/10
=22572/10
=2257.2 RS

difference between ci and si=ci-si
=2257.2-2160
=97.2 RS

DONE
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