Question

find the difference between simple interest and compound interest on rupees 12000 at 9% per annum for 2 years

Answer 1

Answer:

Step-by-step explanation:

P=RS12000

R=9

T=2

W k Th at

Ci-si= p(1+r/100)^t

I hope these W ill helps you

Now u will solve these que

Answer 2

CI,

A=P(1+r/100)^n

A=12000(1+9/100)^2

A=12000*109/100*109/100

A=14257.20

Ci=14257.20-12000=2257.20

SI,

Si1=12000*9*2/100=2160

So their difference is,

CI-SI=2257.20-2160=97.20