Find the difference between the compound interest and the simple interest on 42000 at 12% per annum for 3 years.
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Answer:
= Rs 42000 T=2 years
Let rate = r %
S.I=
100
PRT
=
100
42000×r×2
=840 Rs
For C.I
A=P(1+
100
r
)
n
=42000(1+
100
r
)
2
=42000(1+
10000
r
2
+
50
r
)
=42000+
10
42r
2
+840r
C.I = A - P
=42000+
10
42r
2
+840r−42000
=
10
42r
2
+840r
Given C.I−S.I=105
=
10
42r
2
+840r−840r=105
=
10
42r
2
=105
=42r
2
=1050
=r
2
=25
r=5%
C.I at 2nd year = 42000(1+
100
5
)
2
−42000
=42000(1.1025−1)=4305 Rs
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