Question

Find the difference between the compound interest and the simple interest on Rs. 30000 in 2 years at 8% per annum.​

Answer 1

Answer:

P=Rs.30,000,T=2years and R=10%

⇒ A=P(1+

100

R

)

T

⇒ A=30000×(1+

100

10

)

2

⇒ A=30000×

10

11

×

10

11

∴ A=Rs.36,300

⇒ C.I.=A−P=Rs.36,300−Rs.30,000=Rs.6,300

⇒ S.I.=

100

P×R×T

=

100

30000×10×2

∴ S.I.=Rs.6,000

∴ C.I.−S.I.=Rs.6300−Rs.6000=Rs.300

Step-by-step explanation:

hope it helps

Answer 2

Answer:

Step-by-step explanation:

Principle = p = ?

Rate of Interest = i = 8%

Time = n = 2 yrs

Difference = 30,000 [Ci - Si]

→ $\bold{\boxed{p[(1+i)^n-1] - p * i * t = 30,000}}$

→ $p[(1+0.08)^2-1] - p * 0.08 * 2 = 30,000$

→ $p[(1.08)^2-1] - p(0.16)= 30,000$

→ $p(0.1664) - p(0.16)= 30,000$

→ $(0.0064)p = 30,000$

$\boxed{\bold{P = 46,87,500}}$

Thus the principle amount is 46,87,500