find the difference between the simple interest and compound interest on rupees 8000 at 10% per annum for 3 years
Answers
Answered by
11
Answer:
Step-by-step explanation:Simple interest =(PRT)/100
S.I=(8000×10×3)/100
=2400
CI=A-P
=8000((1+10/100)^3+1)
=2648
So C.I.-S.I.
=2648-2400
=248
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Answered by
1
Answer:
S.I =(8000×10×3)/100
=2400
C.I= A-P
8000(1+10/100)^3+4
=2648
THEN C.I - S.I
2648- 2400
=248
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