Find the difference between the simple interest compound interest on ₹24,000 for 2 YEARS AT 6% PER annum
give the you don't no then I will give
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Answered by
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Hiiiii...
Hope it help u...plz thnx my this & some other answers
P = Rs. 24000,
r = 6% p.a. and
n = 2 years
Compound interest = P(1 + i)n - P
= P[(1 + i)2 - 1]
=24000 (1.062 - 1)
= Rs. 2966.4
Simple interest = Pnr/100
= 24000 × 2 × 6/100
= Rs. 2880
Difference = 2966.4 - 2880 = Rs. 86.4
Hope it help u...plz thnx my this & some other answers
P = Rs. 24000,
r = 6% p.a. and
n = 2 years
Compound interest = P(1 + i)n - P
= P[(1 + i)2 - 1]
=24000 (1.062 - 1)
= Rs. 2966.4
Simple interest = Pnr/100
= 24000 × 2 × 6/100
= Rs. 2880
Difference = 2966.4 - 2880 = Rs. 86.4
Answered by
1
Answer:
₹86.4 is the answer...
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