Question

find the difference between the two number. if first is six time of second and the sum of those are 63.

Answer 1

hello here is your answer ....

➡Let the second number be = x
➡So the first number will be = 6x
➡Sum of the numbers = 63

A/q
x+6x=63
7x=63
x=63/7
x=9

So first number= 6x=6(9)➡54
So second number = x ➡ 9

$<b><i><u>Difference of the first and second number </b></i></u>$

➡54-9
➡45. $\mathfrak{\tiny{\blue{Ans.}}}$

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