How to find radial velocity from angular velocity?
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Consider an arbitrary trajectory r→(t)=rr^ measured from the origin, in polar coordinates (https://en.wikipedia.org/wiki/Polar_coordinate_system). The velocity is then: v→=ddtr→=drdtr^+rdθdtθ^. Relative to the origin, the radial part of the velocity is thus...
Answer 2 of 4
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A particle following a prescribed path has its velocity vector parameterized as v→=e→v where e→ is the tangent vector and v is the speed at that instant. This is kind of obvious. But you use the above to find the tangent vector if you know that...
Answer 3 of 4
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You would be pretty accurate in saying: "the radial velocity responsible only for changing distance between objects and the component perpendicular to it only for change in direction" Why? Consider each case individually: 1) An object has only "radial...
Answer 4 of 4
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Forget about vectors then. Just see it the intuitive physical way. • If you push the speeder to speed up, then you accelerate forward. And speed increases. • If you brake, then you slow down and reduce the speed. This is acceleration again, but negative....
Answer 2 of 4
0 votes
A particle following a prescribed path has its velocity vector parameterized as v→=e→v where e→ is the tangent vector and v is the speed at that instant. This is kind of obvious. But you use the above to find the tangent vector if you know that...
Answer 3 of 4
0 votes
You would be pretty accurate in saying: "the radial velocity responsible only for changing distance between objects and the component perpendicular to it only for change in direction" Why? Consider each case individually: 1) An object has only "radial...
Answer 4 of 4
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Forget about vectors then. Just see it the intuitive physical way. • If you push the speeder to speed up, then you accelerate forward. And speed increases. • If you brake, then you slow down and reduce the speed. This is acceleration again, but negative....
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