find the difference of two numbers whosesum is 12 and is maximum
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find the difference of two numbers whosesum is 12 and is maximum
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Step-by-step explanation:
Let the two numbers be x, 12 – x. Their product p = x (12 – x) = 12x – x2 To find the maximum product. p'(x) = 12 – 2x p”(x) = -2 p'(x) = 0 ⇒ 12 – 2x = 0 ⇒ 2x = 12 ⇒ x = 6 at x = 6, p”(x) = -2 = -ve ⇒ p is maximum at x = 6 when x = 6, 12 – x = 12 – 6 = 6 So the two numbers are 6, 6
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