Math, asked by arrowgirl3244, 2 days ago

Find the difference quotient of the function, V(x) = x2 and use it to find the average rate of change of V as h 120 changes from 10 to 10.05 meters.

3x2 + 3 xh +h2 120 average rate of change from 10 to 10.05 = 2.513 cubic meters per meter

3x + n2 average rate of change from 10 to 10.05 -0.250 cubic meters per meter 120

3x²n+h² 120 average rate of change from 10 to 10.05 = 0.125 cubic meters per meter 1

3x2 + n2, average rate of change from 10 to 10.05 - 2.500 cubic meters per meter 120​

Answers

Answered by Anonymous
0

3x2 + 3 xh +h2 120 average rate of change from 10 to 10.05 = 2.513 cubic meters per meter

3x + n2 average rate of change from 10 to 10.05 -0.250 cubic meters per meter 120

3x²n+h² 120 average rate of change from 10 to 10.05 = 0.125 cubic meters per meter 1

3x2 + n2, average rate of change from 10 to 10.05 - 2.500 cubic meters per meter 120

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Answered by chrisfrankieharvey
2

Answer: The answer is the first option

Step-by-step explanation:

I just did the work on edgenuity.

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