Question

find the different solutions of the equation 3x-2y-4=0​

Answer 1

Answer:

mark brainliest

Step-by-step explanation:

3x−2y−4=0

⇒2y=3x−4

⇒y=  

2

3

​

x−2  ....(i)

This is in the slope-intercept form,

y=mx+c

and comparing equation (i) with it, we get,

m=  

2

3

​

 and c=−2

⇒ Thus, slope of the line is 3 and y-intercept is −2.

Answer 2

Different solutions of equation 3x-2y-4=0 are

1. x = 0, y = -2
2. x = $\frac{4}{3}$, y = 0
3. x = 1, y = $-\frac{1}{2}$

Step-by-step explanation:

The solutions of the equation ( 3x - 2y - 4 = 0) can be found out by substituting values of any variable x or y and then solving to find the value of other variable.

1. Let x = 0, then the equation becomes,

$(3 \times 0) -2y -4 = 0$

$-2y = 4$

$y =\frac{4}{-2}= -2$

So the first solution is x = 0, y = -2.

2. Let y = 0, then the equation becomes,

$3x -(2\times 0) -4 = 0$

$3x = 4$

$x = \frac{4}{3}$

So the second solution is x = $\frac{4}{3}$, y = 0.

3. Let x = 1, then the equation becomes,

$(3 \times 1) -2y -4 = 0$

$3-2y = 4$

$-2y = 4-3$

$-2y = 1$

$y =\frac{1}{-2}= \frac{-1}{2}$

So the first solution is x = 1, y = $-\frac{1}{2}$.

Other solutions can be found out in the same way.