find the differentation of d/dx sin^-1 (cos x)
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Answer:
± 1
Step-by-step explanation:
since....
cos x = sin ( π/2 - x ) or - sin ( π/2 + x )
sin' ( cos x ) = sin' [ sin ( π/2 - x ) ] or
sin' ( cos x ) = sin' [ - sin ( π/2 + x ) ]
hence..,....
sin' ( cos x ) = ± (π/2 - x)
now ....
d/dx [ sin ' ( cos x ) ]
= d/dx [ ± (π/2 - x ) ]
= ± ( 0 - 1 )
= ± 1
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Answer's in the pic bro.
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