Question

Find the differentiation of cos(ax² +b), w.r.t. x
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Answer 1

Answer:

$= \frac{d}{dx} cos ({ax}^{2} + b) \\ = \frac{d}{dx} cos( {ax}^{2} + b) \frac{d}{dx} ( {ax}^{2} + b) \\ \ \\ = - sin( {ax}^{2} + b).2ax \\ = - 2ax \: sin( {ax}^{2} + b)$