Question

How much water should be added to 20g of potassium chloride to
obtain 20% potassium chloride solution?

Answer 1

Explanation:

i hope this will help you to understand

Answer 2

Given:-

→Mass of Potassium Chloride (solute)=20g

→Percentage of Potassium Chloride in the solution/Concentration of the solution= 20%

To find:-

→Mass of water(Solvent)

Solution:-

Let the required mass of water be x.g

Here,mass of solute is given and we have taken mass of solvent as x. So,firstly let's find the total mass of the solution.

Mass of Solution:-

=>Mass of solute+Mass of solvent

=>(20+x) g

Now,we know that :-

Percentage of solute in a solution/Concentration of a solution---

=>Mass of Solute/Mass of solution×100

$= > \frac{20}{20 + x} \times 100 = 20$

$= > \frac{2000}{20 + x} = 20$

$= > 2000 = 20(20 + x)$

$= > 2000 = 400 + 20x$

$= > 20x = 2000 - 400$

$= > 20x = 1600$

$= > x = \frac{1600}{20}$

$= > x = 80g$

Thus,80g of water should be added to the solution.