find the digits A and c 3a ×12 c.84
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Solution.
(a) 24
24 = 1 x 24
24 = 2 x 12
24 = 3 x 8
24 = 4 x 6
Therefore, all the factors of 24 are: 1, 2, 3, 4, 6, 8, 12 and 24.
(b) 15
15 = 1 x 15
15 = 3 x 5
Therefore, all the factors of 15 are: 1, 3, 5 and 15.
(c) 21
21 = 1 x 21
21 = 3 x 7
Therefore, all the factors of 21 are: 1, 3, 7 and 21.
(d) 27
27 = 1 x 27
27 = 3 x 9
Therefore, all the factors of 27 are: 1, 3, 9 and 27.
(e) 12
12 = 1 x 12
12 = 2 x 6
12 = 3 x 4
Therefore, all the factors of 12 are: 1, 2, 3, 4, 6 and 12.
(f) Factors of 20 are:
20 = 1 x 20
20 = 2 x 10
20 = 4 x 5
Therefore, all the factors of 20 are: 1, 2, 4, 5, 10 and 20.
(g) Factors of 18 are:
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