Question

find the dimension of a rectangle whose perimeter is 112 cm and whose breadth is 4 cm less than half its length​

Answer 1

Answer:

Let breadth be b and length be 2(4+b)

perimeter=2(l+b)

112=2(8+2b+b)

112=16+6b

6b=96

b=16

breadth=16cm

length=40cm