You have
a great bond with
one of ur family member... horrale
an incident
that made you realise
worth at the person
the
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Answer:
[math]F=A(B+C'D)+BC'=AB+ AC'D+BC'[/math]
[math]F=\overline{\overline{AB+ AC'D+BC'}}[/math]
Using Demorgans thorem,
[math]F=\overline{\overline{(AB)})\; \overline{(AC'D})\;\overline{(BC')}}[/math]
To be precise,
[math]F=\overline{\overline{(AB)}\; \overline{(A\overline{C}\;D)}\;\overline{(B\;\overline{C}})}[/math]
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