Question

find the dimension of a rectangle with a perimeter of 54 M if its length is 3 M more than twice its width

Answer 1

Hey Mate
your answer is here
let width of rectangle = w m
then lenght = 3+2w m

given that ,
perimeter = 54 m
so,

54 = 2(w+3+2w)
27 = 3w+3

W = 8 m & lenght = 3+2×8 = 19 m

Thanks

Answer 2

width of rectangle = w m

then lenght = 3+2w m

given that ,

perimeter = 54 m

so,

54 = 2(w+3+2w)

27 = 3w+3

W = 8 m & lenght = 3+2×8 = 19 m