Question

find the dimension of a rectangular Park whose perimeter is 60 M and radius 200m

Answer 1

Answer:

Step-by-step explanation:

Given Find the dimension of a rectangular Park whose perimeter is 60 M and area 200 m

Perimeter = 60 m

2 (l + b) = 60 m

l + b = 60/2 = 30

b = 30 - l

Now Area = 200 m

l x b = 200

l x (30 - l) = 200

30 l -  l ^2 - 200 = 0

l^2 - 30 l - 200 = 0

l(l - 20) - 10 (l - 20) = 0

(l - 20)(l - 10) = 0

l = 20, 10

l = 10 m

So now area = l x b

           200 = 10 x b

             b = 200 / 10

            b = 20 m

Answer 2

Answer:

20 and 10

Step-by-step explanation:

2[l+b]=60

[l+b}=30

l*b=200

so similar to how we split the middle term, we have a sum and a product

so l=20 and b=10,or vice versa.

hope it helps you ,if it does please mark brainliest.