Question

if 3+√5/3-√5=a+b√5 then find the value of a and b.​

Answer 1

3+√5/3-√5=a+b√5

9+√5-3√5=3a+3b√5

from here it will come

9-2√5=3a+3b√5

a=3,b=-2/3 by taking 3a=9 and 3b√5=-2√5

Answer 2

Answer:

3+√5/3-√5=a+b√5

Firstly cross out the numerator 3 and the denominator 3 since they can cancel out which leaves you with,

√5-√5=a+b√5

Now for the LHS collect like terms:

√5=a+b√5

Do thee inverse operation for √5 on the RHS

√5/√5=a+b√5/√5

1=a+b+1

1-1=a+b+1-1

a= 0 or b=0

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If I am wrong please correct me.

But hope this helps.