Find the dimension of coefficient of viscosity?
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As we know that it isMathematically proven that,
Coefficient of viscosity (η)= Fr/Av ——- F= tangential Force, Area, r= distance between the layers, v= velocity.
Dimensional Formula of Force = M1L1T-2.
Dimensional Formula of Area= M0L2T0.
Dimensional Formula of distance= M0L1T0.
Dimensional Formula of velocity= M0L1T-1.
Putting these values in above equation we get,
[η]= [M1L1T-2][M0L1T0] / [M0L2T0] [M0L1T-1] = [M1L-1T-1]
Dimensional Formula of Coefficient of viscosity (η)=[M1L-1T-1]
SI unit of Coefficient of viscosity (η) is Pascal-second
PLEASE MARK MY ANSWER AS A BRAINLIEST ANSWER.
Coefficient of viscosity (η)= Fr/Av ——- F= tangential Force, Area, r= distance between the layers, v= velocity.
Dimensional Formula of Force = M1L1T-2.
Dimensional Formula of Area= M0L2T0.
Dimensional Formula of distance= M0L1T0.
Dimensional Formula of velocity= M0L1T-1.
Putting these values in above equation we get,
[η]= [M1L1T-2][M0L1T0] / [M0L2T0] [M0L1T-1] = [M1L-1T-1]
Dimensional Formula of Coefficient of viscosity (η)=[M1L-1T-1]
SI unit of Coefficient of viscosity (η) is Pascal-second
PLEASE MARK MY ANSWER AS A BRAINLIEST ANSWER.
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Answer:
Coefficient of viscosity = F × r × [A × v]⁻¹
η = F × r × [A × v]⁻¹
η = MLT⁻² × L × [L²× LT⁻¹]⁻¹
η = MLT⁻² × L × L⁻² × L⁻¹T
η = MLT⁻² × L⁻¹ × L⁻¹T
η = MLT⁻² × L⁻²T
η = ML⁻¹T⁻¹
hope this helps u............
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