find the dimension of magnetic field B .. Given equation is F =qvB
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F=qvB
Force = MLT^-2
CHARGE = AT
VELOCITY = LT^-1
MAGNETIC FIELD = FORCE/CHARGE×VELOCITY
MLT^-2/AT×LT^-1
MA^-1T^-2
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Answer:
Magnetic field, (B)
F = qVB (given and wkt)
B = F/qV ----- (1)
F = MLT^(-2)
q = AT
V = LT^(-2)
Putting all in (1)
B = MLT^(-2)/ATLT^(-2)
[B] = [MT^(-2)A^(-1)]
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