Question

Find the dimension of the quantity v in the equation
v = {πP(a2 – x2) } / (2ηL)
where a is the radius and L length of the tube in which the fluid of coefficient of viscosity η is flowing, x is the distance from the axis and P is the pressure difference​

Answer 1

Step-by-step explanation:

Volume per sec = L^3 T^-1

Now according to above equation

V= P r^4 / ( neta ) l

=( M L^-1 T^-2 ) ( L^4 )

-------------------------------

( M L^-1 T^-1 ) ( L )

= L^3 T^-1

Hence proved !!!

Answer 2

Answer:

Step-by-step explanation:

Volume per sec = L^3 T^-1

Now according to above equation

V= P r^4 / ( neta ) l

=( M L^-1 T^-2 ) ( L^4 )

-------------------------------

( M L^-1 T^-1 ) ( L )

= L^3 T^-1