find the dimension of x if y = Sin ( xt) where sin Q is dimension less
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Answer:
In the given equation y=Asin(ωt−kx)
Since, trigonometric function is a dimensionless quantity. So, (ωt−kx)is also dimensionless quantity.
So,
(ωt−kx)=1
ωt=1
[ω]= [T]1 =[T] −1kx=1[k]= [L]
1 =[L]
−1
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which one will you choose t or d?
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