Question

Find the dimensions area 4 walls of a room having dimensions 54m × 18m × 15m


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Answer 1

Answer:

since it is a rectangle so area of 4 walls= 2h(l+b)

=2×15(54+18) ==> 30× 72 = 2160 cm²

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Answer 2

✰ Given :-

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The dimensions of a room :-

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• Length = 54 m

• Breadth = 18 m

• Height = 15 cm

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✰ To Find :-

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• The area of 4 walls ( Lateral Surface Area )

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✰ Formula Used :-

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$\star \: \underline{ \boxed{ \sf Lateral \: Surface \: Area_{Cuboid} = 2h ( l + b) }} \: \star$

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✰ Solution :-

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To obtain the required answer, we will put the value in the formula. We get :-

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$\sf \longrightarrow area = 2 \times 15(54 + 18) \\ \\ \\ \sf \longrightarrow area = 30 \times 72 \\ \\ \\ \sf \longrightarrow area = 2160 \: {m}^{2}$

Therefore, the area of the 4 walls is 2160 m².

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