Question

Find the dimensions of a and b in the relation P=(b-x^2)/at, where P is power x is distance and t is time. If you know the answer then only answer

Answer 1

Explanation:

since we have b-x², it means b has same dimension as x². Therefore dimension of b is L²

now dimension of power P is ML²/T³

therefore equating dimensions on both sides,

ML²/T³ = L²/aT

a= T²/M