Find the dimensions of a and b in the relation P=(b-x^2)/at, where P is power x is distance and t is time. If you know the answer then only answer
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Explanation:
since we have b-x², it means b has same dimension as x². Therefore dimension of b is L²
now dimension of power P is ML²/T³
therefore equating dimensions on both sides,
ML²/T³ = L²/aT
a= T²/M
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