Question

Find the dimensions of a×b in the relation p=b-x^2÷a×t

Answer 1

Solution :

Given Relation :

p = $\frac{b-x^2}{a*t}$

To Find dimension of  :

a * b

Knowing the dimensions of rest physical quantities :

• p = Momentum which is m * v

⇒ Kg * m/s

⇒ M * L/T

⇒ MLT-1

• x = length which is represented by L
• T is time

Substituting the Value :

MLT^-1 = b° - L^2/a° *T

(i) b° = L^2

[b°] = [L^2]

(ii) [MLT^-1] = [L^2/a° *T]

[a] = M^-1L^3T^-1

Hence , Our Required answer is a * b which is M^-1L^5T^-1