Question

Find the dimensions of a box whose area is 196 cu. in., whose surface area is 280 sq. in., and whose width is twice its height.

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Answer 1

Let height be "x"

Width = "2x"

Base and top have area (2x)^2 = 4x^2

Sides have area (2x)x=2x^2

Total area = top + bottom + 4(side)

=4x^2 + 4x^2+4(2x^2)

=16x^2

So, 16x^2=280 sq. in.

x^2=17.5

x=4.1833 inch

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Checking:

Volumn = area of base * height

196 = (4x^2)(x)

49=x^3

x=3.659

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Answer 2

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