find the dimensions of (a) electric field (b) magnetic field
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We know that electrostatic force = kq1q2/r²
And electric field= kq1/r²
So we can say field= force/charge
Now force = mass * accn
Accn = metre / time²
So dimensions of force = M¹L¹T^-2
Charge = I(current) * time
So dimensions of charge= A¹T¹
From this dimensions of field comes to be = M¹L¹T^-2/A¹T¹ =
= M¹L¹T^-3 A^-1Answer:
F=qvB and also F=qE
By above equation dimensionally.
Bv=E
Or, B=E/v
Or, 【B】= 【E】/【v】 = 【M L T^-3 A^-1】/ 【L T^-1】
=【M T^-2 A^-1】
Explanation:
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