Math, asked by gsreenivasarao35, 3 months ago

find the dimensions of a rectangle whose peremeter is 28 meters and whose area is 40 square meter

Answers

Answered by anzalnanihas

0

Step-by-step explanation:

perimeter = 28m

area = 40 sq. m

2(l+b) = 28

l+ b = 28/2=14

l×b = 40

length 10m, breadth 4m

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