Question

find the dimensions of a rectangle whose perimeter is 25 cm and area is 39 sq.cm​

Answer 1

Answer:

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Step-by-step explanation:

Area of rectangle = length × breadth

Perimeter of a rectangle = 2 (length + breadth)

Explanation:

Let 'A' be area and 'P' be perimeter of the rectangle

Let 'x' be the width and 'y' be the length

We know that,

Perimeter = 2 (length + breadth)

Hence,

P = 2(x+y)

=> 25 = 2(x+y) (Since, Perimeter = 25 cm)

=> x + y = 25/2

=> y = 25/2 - x ----------------------------- (1)

We know that,

Area of a rectangle = Length × Breadth

Hence,

A = xy -------------------(2)

By substituting the value of y from equation (1) to equation (2) we get,

Area = (25/2 x X)

39 = 25/2 x X

X = 25/2 - 39

X = - 14/2

X = - 7

Therefore, breadth is -7

length = breadth - area

=> y = - 7 - 39

=> y = - 46

Answer 2

Answer::

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