Question

Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40
square meters.​

Answer 1

Answer:

Step-by-step explanation:

Firstly let dimensions a,b

Then ,ATQ- a+b=28-----(1)

and a×b=40

By solving the equations

So, a=40÷b-----(2)

Put (2) in (1)

We get, (40÷b)+b=28

Now solve it

You surely get values of a,b

Answer 2

Question ⏬

Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40

square meters.

Answer⏬

Check out the attachment please.