Find the dimensions of a rectangle whose perimeter is 28 meter and area is 40 square meters
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Given :- Perimeter of rectangle = 28
2 (l + b ) = 28
l + b = 14
l = 14 - b --- (i)
area = 40
l × b = 40
from (i)
( 14 -b ) × b = 40
(14 - b²) = 40
b² - 14b + 40 = 0
After spilliting the zeros you will get...
(length) = 10
(breadth) = 4
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Vittesh2000:
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