Question

find the dimensions of a rectangle with perimeter of 54 M if its length is 3 M more than twice its width

Answer 1

let width be x
let length be 2x+3

perimeter =54m

perimeter of a rectangle = 2 (l+b)
=2 (2x+3+x)=54
=4x+6+2x=54
=6x+6=54
=6x=54-6
=6x=48
=x=48/6
=8

x=8
2x+3=8×2+3
=19

length is on and width is 8 m

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