find the dimensions of rectangle whose perimeter is 112cm and whose breadth is 4 cm less than half its length
Answers
Answered by
2
Answer:
40 x 16 ( in the format l X b)
Step-by-step explanation:
Let 'b' be the breadth and 'l' be the length of the rectangle.
b=l/2 - 4
perimeter,p = 2(l+b)
i.e p = (l + l/2 - 4)*2
p = 3l - 8 = 112
i.e 3l = 120
Therefore, l = 40cm and b = 16cm..
Answered by
1
The length of rectangle = 40 cm and
The breadth of rectangle = 16 cm
Step-by-step explanation:
Given,
The perimeter of rectangle = 112 cm
Let the length of rectangle = x and
The breadth of rectangle =
To find, the length and breadth of rectangle = ?
We know that,
The perimeter of rectangle = 2(l + b)
∴ 2(x + ) = 112
⇒ x + =
⇒
⇒
⇒ 3x = 60 × 2 = 120
⇒ x =
∴ The length of rectangle = 40 cm and
The breadth of rectangle = = 16 cm
Similar questions