if area of right angled triangle is 240mcube and side other than hypotenuse is 30m find perimeter of triangle
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Answered by
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1/2×b ×h =240
1/2 * b * 30 =240
15b=240
b=16 base
by Pythagoras
16^2+30^2=hypo^2
hypo = 34
perimeter = sum of sides
30+34+16=80m
1/2 * b * 30 =240
15b=240
b=16 base
by Pythagoras
16^2+30^2=hypo^2
hypo = 34
perimeter = sum of sides
30+34+16=80m
thashreefams:
bt here the final answr is 16m
Answered by
1
Answer:
We know that,
Area of a triangle = 1/2 × base × height
Here Area of Δ is given = 240 m²
and one side is = 30 m
∴ Area of a triangle = 1/2 × base × height
∴ 240 = 1/2 × base × 30
∴ base = 240 / 15
∴ base = 16 m
So we get second side other than hypotenuse is 16 m
∴ hypotenuse = √(side1)² + (side2)²
∴ hypotenuse = √30² + 16²
∴ hypotenuse = √900 + 256
∴ hypotenuse = √1156
∴ hypotenuse = 34 m
Now Perimeter of Δ = Sum of all sides
∴ Perimeter of Δ = 30 + 34 + 16
∴ Perimeter of Δ = 80 m
Step-by-step explanation:
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