Question

Find the dimensions of rectangle whose perimeter is 60 mtr and area is 200 sq mtr.​

Answer 1

Answer. Therefore the dimensions are 10m and 20m.

Answer 2

Step-by-step explanation:

Let the length and breadth of a rectangle are x.m and y.m respectively , accordingly :-

2.(x+y)= 60. Or x+y = 30. ……………..(1).

and x.y = 200. …………………………….(2)

(x-y)^2. = (x+y)^2 - 4.xy.

(x-y)^2. = (30)^2–4×200.

(x-y)^2. = 100.

or, x - y = 10. …………………………….(3)

Subtracting equation (3) from eqn. (1).

2.y = 20. => y = 20/2 = 10. m. Answer.