Question

Find the dimensions of the constant a and b in the
relation p= (b-x²)/at , where p is power , x is distance
and t is time.​

Answer 1

Answer:

Explanation:

The given relation is P=b−x2at

As x2 is subtracted from b, therefore, the

dimensions of are of x2,i.e.,b=[L2]

we can rewrite relation (i) as P=L2at

or a=L2Pt=L2[ML2T−3][T]=[M−1L0T2]