Physics, asked by Anonymous, 8 months ago

find the dimensions of the potential and then the capacitance given,E=vit and Q=CV

Answers

Answered by richu20
1

Answer:

For the circuit (i), diode has higher voltage at p-side, so it is forward-biased and acts as short.

Thus capacitor discharge through capacitor.

q=q0e−t/RC=CVe−t/RC

at t=RC,q=CVe−CR/CR=CV/e

For the circuit (ii), diode has higher voltage on the n-side, so it is reversed-biased and acts as open circuit.

So the capacitor is isolated and its charge stays the same.

So q=CV

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