find the dimensions of the potential and then the capacitance given,E=vit and Q=CV
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For the circuit (i), diode has higher voltage at p-side, so it is forward-biased and acts as short.
Thus capacitor discharge through capacitor.
q=q0e−t/RC=CVe−t/RC
at t=RC,q=CVe−CR/CR=CV/e
For the circuit (ii), diode has higher voltage on the n-side, so it is reversed-biased and acts as open circuit.
So the capacitor is isolated and its charge stays the same.
So q=CV
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